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18veron02
@18veron02
October 2021
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решите пожалуйста!быстро
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pomoshnik09
1)=у^4-2y²-y+2 p(1)=1-2-1+2=0 p(-1)=1-2+1+2=2 p(2)=16-8-2+2=8 p(1/2)=
=1/16-1/2-1/2+2=1. 1/16
2)= a²+b²-4ab p(1. 2)=1²+2²-4*1*2=1+4-8=-3 p(1. -1)=1²+(-1)²-4*1*-1=1+1+4=6
p(2. 2)= 2²+2²-4*2*2=4+4-16=-8 p(-1. 2)=(-1)²+2²-4*-1*2=1+4+8=13
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Answers & Comments
=1/16-1/2-1/2+2=1. 1/16
2)= a²+b²-4ab p(1. 2)=1²+2²-4*1*2=1+4-8=-3 p(1. -1)=1²+(-1)²-4*1*-1=1+1+4=6
p(2. 2)= 2²+2²-4*2*2=4+4-16=-8 p(-1. 2)=(-1)²+2²-4*-1*2=1+4+8=13