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AndruySurgut
@AndruySurgut
March 2022
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РЕШИТЕ ПОЖАЛУЙСТА !!!!!!!!!!!!!!!!!!!!!!!!!!!
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Alexandr130398
7°30'=7.5°
cos²α-sin²α=cos(2α)
2sinα×cosα=sin(2α
)
8sin7.5°(cos²7.5°-sin²7.5°)cos7.5°=4×2sin7.5°cos7.5°(cos²7.5°-sin²7.5°)=
=4sin15°×cos15°=2×2sin15°×cos15°=2sin30°=2×1/2=1
ответ: 1
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Answers & Comments
cos²α-sin²α=cos(2α)
2sinα×cosα=sin(2α)
8sin7.5°(cos²7.5°-sin²7.5°)cos7.5°=4×2sin7.5°cos7.5°(cos²7.5°-sin²7.5°)=
=4sin15°×cos15°=2×2sin15°×cos15°=2sin30°=2×1/2=1
ответ: 1