July 2022 1 12 Report
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drakerton
drakertondrakerton

Ответ:

x\in (1\frac{5}{9}; 5,4]

Пошаговое объяснение:

\left \{ {{6x-8 > -3(x-2)} \atop {4(x+5) \geq 9x-7}} \right. \\\\\left \{ {{6x-8 > -3x+6} \atop {4x+20 \geq 9x-7}} \right. \\\\\left \{ {{6x+3x > 6+8} \atop {4x-9x \geq -7-20}} \right. \\\\\left \{ {{9x > 14} \atop {-5x \geq -27}} \right. \\\\\left \{ {{x > 1\frac{5}{9}} \atop {x \leq 5,4}} \right. \\\\x\in (1\frac{5}{9}; 5,4]

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