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мясник6
@мясник6
August 2022
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Решите пожалуйста!)))
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миша29112000
5) а^2-9/а^2-6а+9= (а-3)(а+3)/(а-3)^2=а+3/а-3
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Thanks 1
sedinalana
1
16x²-72=0
16x²=72
x²=72/16=18/4
x=-3√2/2 U x=3√2/2
2
12x²-3x==0
3x(4x-1)=0
x=0 U x=1/4
3
4
(4x²-1)/(2x+1)=(2x-1)(2x+1)/(2x+1)=2x-1
5
(a²-9)/(a²-6a+9)=(a-3)(a+3)/(a-3)²=(a+3)/(a-3)
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Answers & Comments
16x²-72=0
16x²=72
x²=72/16=18/4
x=-3√2/2 U x=3√2/2
2
12x²-3x==0
3x(4x-1)=0
x=0 U x=1/4
3
4
(4x²-1)/(2x+1)=(2x-1)(2x+1)/(2x+1)=2x-1
5
(a²-9)/(a²-6a+9)=(a-3)(a+3)/(a-3)²=(a+3)/(a-3)