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pokipoki
@pokipoki
August 2022
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Решите, ПОЖАЛУЙСТА,очень нужно,спасибо :)
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nKrynka
Sin2x / (1 + ctgx) = 0
sin2x = 0
2x = πk, k∈z
x = πk/2, k∈Z
1 + ctgx ≠ 0
ctgx ≠ - 1
x ≠ - π/4 + πn, n∈Z
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Answers & Comments
sin2x = 0
2x = πk, k∈z
x = πk/2, k∈Z
1 + ctgx ≠ 0
ctgx ≠ - 1
x ≠ - π/4 + πn, n∈Z