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a6880573
@a6880573
June 2022
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Решите пожалуста:
3с(с-2)-(с-3)(с-1)
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FickenLuder
3с^2-6с-(с^2-с-3с+3)=3с^2-6с-с^2+с+3с-3=2с^2-2с-3^ - это степень, если что:)
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Rinatking
3c(c-2)-(c-3)(c-1)=0
(3c-1)(c-2)(c-3)(c-1)=0
3c-1=0,c-2=0,c-3=0,c-1=0
3c=1 c=2,c=3,c=1
c=1/3
1 votes
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Answers & Comments
(3c-1)(c-2)(c-3)(c-1)=0
3c-1=0,c-2=0,c-3=0,c-1=0
3c=1 c=2,c=3,c=1
c=1/3