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MK20
@MK20
March 2022
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reshite pozhauista!!! srochno!
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mmb1
Verified answer
Одз
x>y
x>-y
log(0.2) (x+y)=-2
log(0.2) (x-y) = -1
(1/5)^(-2) = x+y
(1/5)^(-1) = x-y
x+y=25
x-y=5
складываем
x+y+x-y=25+5
2x=30
x=15
15+y=25
y=10
15>10 удовлетворяет ОДЗ
15>-10 тоже
ответ (15 10)
1 votes
Thanks 1
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Answers & Comments
Verified answer
Одзx>y
x>-y
log(0.2) (x+y)=-2
log(0.2) (x-y) = -1
(1/5)^(-2) = x+y
(1/5)^(-1) = x-y
x+y=25
x-y=5
складываем
x+y+x-y=25+5
2x=30
x=15
15+y=25
y=10
15>10 удовлетворяет ОДЗ
15>-10 тоже
ответ (15 10)