Ответ:

1)

(3-x)²-(x-3)(x+3)+5x+22 = 9-6x+x²-x²+9+5x+22=40-x

2)

a)3m-3mn=3m(1-n) б)8x³-12x^6=4x³(2-3x³) в)49-c²/9=(7-c/3)(7+c/3) г)64+16y+y²=(8+y)²

3)

y(1,7-x)-4,3(1,7-x)=y*1,7-x*y-4,3*1,7+4,3*x=12,3*1,7-0,2*12,3-4,3*1,7+4,3*0,2=12

4)

a)18a²+12ab+2b²=2(9a²+6ab+b²)=2(3a+b)²

б)3a(b+4)+2c(-b-4)=3a(b+4)-2c(b+4)=(b+4)(3a-2c)

в)x²+2xy-4x-8y=x(x+2y)-4(x+2y)=(x+2y)(x-4)

5)

x²(x+2)-(x+2)(x²-x+3)=0

(x+2)(x²-(x²-x+3))=0

(x+2)(x²-x²+x-3)=0

x+2=0. x-3=0

x1=-2. x2=3