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alinasuper77
@alinasuper77
July 2022
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Решите пж (а-2)(а+2)-2а(5-а)
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ruh5
(a-2)(a+2)-2a(5a-a)=a^2-4-10a+2a^2
3a^2-10a-4=0
D=100-4*3*(-4)=100+
48=148 корень148=2корня37
a1=10+2корня37/6=2(5+
корень37)/6=5+
корень37/3
a2=10-2корня37/6=2(5-
корень37)/6=5-
корень37/3
но это не точно
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Answers & Comments
3a^2-10a-4=0
D=100-4*3*(-4)=100+48=148 корень148=2корня37
a1=10+2корня37/6=2(5+корень37)/6=5+корень37/3
a2=10-2корня37/6=2(5-корень37)/6=5-корень37/3
но это не точно