Ответ:
х^2 -15 -16=0 D=b^2 -4ac=225-4×1*(-16)=225+64=289=17^2> 0 х1=15+17/2×1=15+17/2=32/2=16 х2=15-17/2×1=15-17/2=-2/2=-1 х1=16; х2=-1
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Ответ:
х^2 -15 -16=0 D=b^2 -4ac=225-4×1*(-16)=225+64=289=17^2> 0 х1=15+17/2×1=15+17/2=32/2=16 х2=15-17/2×1=15-17/2=-2/2=-1 х1=16; х2=-1