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koshka99
@koshka99
July 2022
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решите пж неравенство: 1,5х+1 <= |х-1|
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danonmi77
1,5х+1 ≤ |х-1|
1,5x-|x-1| ≤-1
1) При x-1≥0 (x≥1):
1,5x-(x-1)≤ -1
1,5x-x+1+1≤0
0,5x≤ -2
x≤ -4 ; x≥1 => x ∉ R
2) При x-1<0 (x<1):
1,5x-(-(x-1))≤ -1
1,5x+x-1+1≤0
2,5x≤0
x≤0 => x ∈ (-∞;0]
Ответ: (-∞; 0]
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Answers & Comments
1,5x-|x-1| ≤-1
1) При x-1≥0 (x≥1):
1,5x-(x-1)≤ -1
1,5x-x+1+1≤0
0,5x≤ -2
x≤ -4 ; x≥1 => x ∉ R
2) При x-1<0 (x<1):
1,5x-(-(x-1))≤ -1
1,5x+x-1+1≤0
2,5x≤0
x≤0 => x ∈ (-∞;0]
Ответ: (-∞; 0]