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yuldashev1910
@yuldashev1910
July 2022
1
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Решите пж упр 205 а) (6-х)(х+6)-(х-11)х=36
Б) 1-3у-3-у=0
---- ---
11 5
В)9х(квадрате) -12х(квадрате)-11)(3х+8)=1
------------------------------------
4
Г)(у+1)(квадрате) - 1-у(квадрате)=4
-------------------- ------------------
12 24 пж помогите
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aydan2002
А) 6х+36-х^2-6х-(х-11)х=36
-х^2-(х-11)х=0
-х^2-х^2+11х=0
-2х^2+11х=0
-х(-2*(-х)*11)=0
-х(2х-11)=0
-х=0
2х-11=0
х1=0
х2=11/2
Б) -2у-4у=0
-4у=2
у=-2/4
у=-1/2=-0,5
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yuldashev1910
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Answers & Comments
-х^2-(х-11)х=0
-х^2-х^2+11х=0
-2х^2+11х=0
-х(-2*(-х)*11)=0
-х(2х-11)=0
-х=0
2х-11=0
х1=0
х2=11/2
Б) -2у-4у=0
-4у=2
у=-2/4
у=-1/2=-0,5