решите пж................ Created by Mako111111. algebra-ru

решите пж...

Mako111111 @Mako111111

July 2022 1 3 Report

решите пж...............

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sharadi

Verified answer

С₍n₎⁹= n!/(9! *(n - 9)!)= (n-8)(n-7)(n-6)(n-5)(n-4)(n-3)(n-2)(n-1)n/9!
С₍n₎⁸ = n!/(8! *(n-8)! = (n-7)(n-6)(n-5)(n-4)(n-3)(n-2)(n-1)n/8!
приводим к общему знаменателю. Он = 9!
возимся с числителем:
(n-8)(n-7)(n-6)(n-5)(n-4)(n-3)(n-2)(n-1)n/9! +
+ (n-7)(n-6)(n-5)(n-4)(n-3)(n-2)(n-1)n/8! =
=(n-8)(n-7)(n-6)(n-5)(n-4)(n-3)(n-2)(n-1)n+
+9(n-7)(n-6)(n-5)(n-4)(n-3)(n-2)(n-1)n=
=(n-7)(n-6)(n-5)(n-4)(n-3)(n-2)(n-1)n(n-8+9)=
=(n-7)(n-6)(n-5)(n-4)(n-3)(n-2)(n-1)n(n+1)
теперь правая часть равенства:
С₍n+1₎⁹= (n+1)!/(9!*(n+1 -9)!)=(n+1)!/(9!*(n-8)!)=
=(n-7)(n-6)(n-5)(n-4)(n-3)(n-2)(n-1)n(n+1)/9!

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geometriya pzh

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