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bigdinara
@bigdinara
June 2022
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решите пжл уравнение 9^{х-1}+7=4( 3^{х-1}+1)
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Answers & Comments
DaniilTalagaev
9^(x-1) + 7 = 4 (3^(x-1) + 1)
Пусть a = (x-1)
9^a + 7 = 4 (3^a +1)
9^a - 4*3^a = 4 - 7
3^(2a) - 4*3^a = -3
Пусть t = 3^a
t^2 - 4t + 3 = 0
D = 16 - 4*3 = 4
t = (4 ± 2) / 2 = 2
± 1
3^a = 2
± 1
3^a = 3; 3^a = 1
a = 1; a = 0
x-1 = 1 x-1 = 0
x = 2 x = 1
Ответ: 1; 2
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Answers & Comments
Пусть a = (x-1)
9^a + 7 = 4 (3^a +1)
9^a - 4*3^a = 4 - 7
3^(2a) - 4*3^a = -3
Пусть t = 3^a
t^2 - 4t + 3 = 0
D = 16 - 4*3 = 4
t = (4 ± 2) / 2 = 2 ± 1
3^a = 2 ± 1
3^a = 3; 3^a = 1
a = 1; a = 0
x-1 = 1 x-1 = 0
x = 2 x = 1
Ответ: 1; 2