решите пжжжжжжжжжжжжж. Created by Djdjdjdjd. algebra-ru

1. +3=(x-2)*(x+2)-14x+49+3=--14x-=-4-5214x=-56x=-42. (x+1)*(x+2)-(x-3)*(x+4)=6+2x+x+2--4x+3x+12=62x=6-142x=-8x=-43. 8m*(1+2m)-(4m+3)*(4m-3)=2m8m+-()+9=2m6m=-9m=-=1.54. -2x*(4+2x)=114-12x+9-8x-4=11-20x=15x=-=0.755. (8-9a)*a=-40(6-3a)(6+3a)8a-9=-40*36-98a=-1440a=-1806. -(x-5)*(x+5)=79+12x+36-+25=7912x=18x==1.57. (6y+2)*(5-y)=47-(2y-3)*(3y-1)30y-6+10-2y=47-6+2y+9y-3y20y=37y==1.85

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Djdjdjdjd @Djdjdjdjd

March 2022 1 10 Report

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ivanshumilov2 1. $(x-7)^{2}$ +3=(x-2)*(x+2)
$x^{2}$ -14x+49+3= $x^{2}$ - $2^{2}$
$x^{2}$ -14x- $x^{2}$ =-4-52
14x=-56
x=-4
2. (x+1)*(x+2)-(x-3)*(x+4)=6
$x^{2}$ +2x+x+2- $x^{2}$ -4x+3x+12=6
2x=6-14
2x=-8
x=-4
3. 8m*(1+2m)-(4m+3)*(4m-3)=2m
8m+ $4m^{2}$ -( $4m^{2}$ )+9=2m
6m=-9
m=- $\frac{9}{6}$ =1.5
4. $(2x-3)^{2}$ -2x*(4+2x)=11
4 $x^{2}$ -12x+9-8x-4 $x^{2}$ =11
-20x=15
x=- $\frac{15}{20}$ =0.75
5. (8-9a)*a=-40(6-3a)(6+3a)
8a-9 $a^{2}$ =-40*36-9 $a^{2}$
8a=-1440
a=-180
6. $(x+6)^{2}$ -(x-5)*(x+5)=79
$x^{2}$ +12x+36- $x^{2}$ +25=79
12x=18
x= $\frac{18}{12}$ =1.5
7. (6y+2)*(5-y)=47-(2y-3)*(3y-1)
30y-6 $y^{2}$ +10-2y=47-6 $y^{2}$ +2y+9y-3y
20y=37
y= $\frac{37}{20}$ =1.85

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