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September 2021
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Решите рациональное уравнение, через дискриминант
26.6(г) 26.7(г)
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белочка2369
26.6
(2x+3)/(x+2) = (3x+2)/x
(2x²+3x)/x(x+2) = (3x²+2x+6x+4)/x(x+2)
2x²+3x = 3x²+2x+6x+4
2x²+3x-3x²-2x-6x-4 = 0
-x²-5x-4 = 0 I *(-1)
x²+5x+4 = 0
D=√25-16=√9=3.
-5+3 -2
x₁ = _____ = ____ =
-1.
2 2
-5-3 -8
x₂ = ____ = ____ =
-4.
2 2
Ответ : -4 ; -1.
26.7
(2х-1)/(х+7) = (3х+4)/(х-1)
(2x
²-x-2x+1
)/(х+7)(х-1) = (3x
²+4x+21x+28
)/(х+7)(х-1)
2x²-x-2x+1 = 3x²+4x+21x+28
2x²-x-2x+1-3x²-4x-21x-28 = 0
-x²-28x-27 = 0 I *(-1)
x²+28x+27 = 0
D=√784-108=√676=26.
-28+26 -2
x₁ = _______ = ____ =
-1.
2 2
-28-26 -54
x₂ = _______ = ____ =
-27.
2 2
Ответ : -27 ; -1.
1 votes
Thanks 1
белочка2369
ой, я 2 ур-е забыла, сейчас исправлю
белочка2369
вот, дописала
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Answers & Comments
(2x+3)/(x+2) = (3x+2)/x
(2x²+3x)/x(x+2) = (3x²+2x+6x+4)/x(x+2)
2x²+3x = 3x²+2x+6x+4
2x²+3x-3x²-2x-6x-4 = 0
-x²-5x-4 = 0 I *(-1)
x²+5x+4 = 0
D=√25-16=√9=3.
-5+3 -2
x₁ = _____ = ____ = -1.
2 2
-5-3 -8
x₂ = ____ = ____ = -4.
2 2
Ответ : -4 ; -1.
26.7
(2х-1)/(х+7) = (3х+4)/(х-1)
(2x²-x-2x+1)/(х+7)(х-1) = (3x²+4x+21x+28)/(х+7)(х-1)
2x²-x-2x+1 = 3x²+4x+21x+28
2x²-x-2x+1-3x²-4x-21x-28 = 0
-x²-28x-27 = 0 I *(-1)
x²+28x+27 = 0
D=√784-108=√676=26.
-28+26 -2
x₁ = _______ = ____ = -1.
2 2
-28-26 -54
x₂ = _______ = ____ = -27.
2 2
Ответ : -27 ; -1.