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жук234
@жук234
July 2022
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Решите с помощью метода интервалов неравенство:
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ВладимирБ
Verified answer
Решение смотри в приложении
2 votes
Thanks 1
sedinalana
Verified answer
А
(x-3)(x-4)/(x-5)>0
x=3 x=4 x=5
_ + _ +
------------(3)------------(4)-------------------(5)--------------
x∈(3;4) U (5;∞)
б
(x+3)(x+4)/(x+5)<0
x=-3 x=-4 x=-5
_ + _ +
------------(-5)------------(-4)-------------------(-3)--------------
x∈(-∞;-5) U (-4;-3)
в
(x+1)(x-1)/(x-3)<0
x= -1 x=1 x=3
_ + _ +
------------(-1)------------(1)-------------------(3)--------------
x∈(-∞;-1) U (1;3)
г
(x-0)(x-3)/(x+4)>0
x=0 x=3 x=-4
_ + _ +
------------(-4)------------(0)-------------------(3)--------------
x∈(-4;0) U (3;∞)
д
x/(x-3)(x+4)>0
x=0 x=3 x=-4
_ + _ +
------------(-4)------------(0)-------------------(3)--------------
x∈(-4;0) U (3;∞
е
x/(x+1)(x-8)<0
x=0 x=-1 x=8
_ + _ +
------------(-1)------------(0)-------------------(8)--------------
x∈(-∞;-1) U (0;8)
0 votes
Thanks 0
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Answers & Comments
Verified answer
Решение смотри в приложенииVerified answer
А(x-3)(x-4)/(x-5)>0
x=3 x=4 x=5
_ + _ +
------------(3)------------(4)-------------------(5)--------------
x∈(3;4) U (5;∞)
б
(x+3)(x+4)/(x+5)<0
x=-3 x=-4 x=-5
_ + _ +
------------(-5)------------(-4)-------------------(-3)--------------
x∈(-∞;-5) U (-4;-3)
в
(x+1)(x-1)/(x-3)<0
x= -1 x=1 x=3
_ + _ +
------------(-1)------------(1)-------------------(3)--------------
x∈(-∞;-1) U (1;3)
г
(x-0)(x-3)/(x+4)>0
x=0 x=3 x=-4
_ + _ +
------------(-4)------------(0)-------------------(3)--------------
x∈(-4;0) U (3;∞)
д
x/(x-3)(x+4)>0
x=0 x=3 x=-4
_ + _ +
------------(-4)------------(0)-------------------(3)--------------
x∈(-4;0) U (3;∞
е
x/(x+1)(x-8)<0
x=0 x=-1 x=8
_ + _ +
------------(-1)------------(0)-------------------(8)--------------
x∈(-∞;-1) U (0;8)