Verified answer

4)

дано

m(H2) = 12g

η(NH3) = 90%

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m прак(NH3)= ?

H2+3N2-->2NH3

M(H2) = 2 g/mol

n(H2) = m/M = 12/2 =6 mol

n(H2) = 2n(NH3)

n(NH3) = 6*2/1 = 12 mol

M(NH3) = 17 g/mol

m теор(NH3) = n(NH3)*M(NH3) = 12 * 17 = 204 g

m практ(NH3) = m теор(NH3) * η(NH3) / 100% = 204 * 90% / 100% = 183.6 g

ответ 183.6 г

5)

дано

m(Zn) = 13 g

m(HCL) = 14.2 g

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V(H2)-?

M(Zn) = 65 g/mol

n(Zn) = m/M = 13 / 65 = 0.2 mol

M(HCL) = 36.5 g/mol

n(HCL) = m/M = 14.2 / 36.5 = 0.39 mol

n(Zn) < n(HCL)

Zn+2HCL-->ZnCL2+H2

n(Zn) = n(H2) = 0.2 mol

V(H2) = n(H2) * Vm = 0.2 * 22.4 = 4.48 L

ответ 4.48 л