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maks2965
@maks2965
August 2022
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Решите систему
2у-х=7
Х²-ху-у²=29
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kak1234567
X = 2y - 7
(2y - 7)^2 - (2y - 7) - y^2 = 29
4y^2 - 28y + 49 -2y + 7 -y^2 = 29
3y^2 - 30y + 27 =0 /3
y^2 - 10y + 9 = 0
D1 = 25 - 1 × 9 = 16
y1 = 9 y2 = 1
x1 = 2 × 9 - 7 = 11
x2 = 2 × 1 - 7 = -5
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Answers & Comments
(2y - 7)^2 - (2y - 7) - y^2 = 29
4y^2 - 28y + 49 -2y + 7 -y^2 = 29
3y^2 - 30y + 27 =0 /3
y^2 - 10y + 9 = 0
D1 = 25 - 1 × 9 = 16
y1 = 9 y2 = 1
x1 = 2 × 9 - 7 = 11
x2 = 2 × 1 - 7 = -5