Решите систему.
х+3у=11
2х+у^2(игрик в квадрате)=14
2х+у^2=14
1)х+3у=11
х=11-3у
2)2х+у^2=14
2(11-3у)+у^2=14
22-6у+у^2=14
22-6у+у^2-14=0
у^2-6у+8=0
D=b^2-4ac
D=(-6)^2-4*1*8=36-32=4
у1=(6-2)/2=2
у2=(6+2)/2=4
3)х1=11-3*2=5
х2=11-3*4=-1
Ответ:(2;5),(4;-1)
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Answers & Comments
х+3у=11
2х+у^2=14
1)х+3у=11
х=11-3у
2)2х+у^2=14
2(11-3у)+у^2=14
22-6у+у^2=14
22-6у+у^2-14=0
у^2-6у+8=0
D=b^2-4ac
D=(-6)^2-4*1*8=36-32=4
у1=(6-2)/2=2
у2=(6+2)/2=4
3)х1=11-3*2=5
х2=11-3*4=-1
Ответ:(2;5),(4;-1)