решите систему, пожалуйста: 3х+4у=114 5х=6у. Created by Zhakastoroom. algebra-ru

решите систему, пожалуйста: 3х+4у=114 5х=6у...

$\left\{\begin{array}{l}3x+4y=114\, |\cdot 3\\5x=6y\, |\cdot 2\end{array}\right\; \; \left\{\begin{array}{l}9x+12y=342\\10x-12y=0\end{array}\right\; \oplus \; \left\{\begin{array}{l}4y=114-3x\\19x=342\end{array}\right\\\\\\\left\{\begin{array}{l}4y=60\\x=18\end{array}\right\; \; \left\{\begin{array}{l}y=15\\x=18\end{array}\right\; \; \; \to \; \; \; (18;15)$

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Ответ:(x,y)=(18,15)

Объяснение:

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