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CherryPunch
@CherryPunch
July 2022
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Решите систему уравнений:
1)2х+y=5
3x-4y=2
2)x-2y=-1
3x+4y=17
3)2x-6y=0
x+y=-4
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rostikjanichin
Ответ: (2;-1)2у=-5+3х=-5+3=-2
у=-15х+(-10+6х)=1
5х-10+6х=1
11х=113(0.2-0.8y )-2y=5 2x-1+3y=0у=-1 2х=(-3)(-1)+1-11у=11х=2 5x+4y=1 6x-2y=14x=0.2-0.8(-1)= 0.2+0.8=1 x=22. 2х=-3у+1
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Answers & Comments
у=-15х+(-10+6х)=1
5х-10+6х=1
11х=113(0.2-0.8y )-2y=5 2x-1+3y=0у=-1 2х=(-3)(-1)+1-11у=11х=2 5x+4y=1 6x-2y=14x=0.2-0.8(-1)= 0.2+0.8=1 x=22. 2х=-3у+1