решите систему уравнений
2х + у2 = 6,
х + у = 3.
x=3-y
2*(3-y)+y2=6
6-2y+y2-6=0
y2-2y=0
y(y-2)=0
y=0 или у-2=0; у=2
х=3
х=1
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
x=3-y
2*(3-y)+y2=6
6-2y+y2-6=0
y2-2y=0
y(y-2)=0
y=0 или у-2=0; у=2
х=3
х=1