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Notarius
@Notarius
July 2022
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Решите систему уравнений
2x^2+3y^2=11
4x^2+6y^2=11x
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Vas61
2x²+3y²=11 умножим на 2 обе части, получим 4x²+6y²=22 и подставим во второе уравнение, получим
22=11x
x=2
y²=(11-2x²)/3 y=(11-2×4)/3=1 y=-1 y=1
ответ (2;-1) (2;1)
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Answers & Comments
22=11x
x=2
y²=(11-2x²)/3 y=(11-2×4)/3=1 y=-1 y=1
ответ (2;-1) (2;1)