Решите систему уравнений, которая на фото ВАРИАНТЫ ОТВЕТА : а) (3;-4) б) (-1;2) в)(1;-2) г)(-3;4). Created by Топьскя. algebra-ru

Умножаем первое уравнение на 4.Получим систему{х+3-2(у+2)=0{3х+у=1{x-2y=1{3x+y=1Умножаем второе уравнение на 2{x-2y=1{6x+2y=2Складываем7х=3х=3/7у=1-3х=1-(9/7)=-2/7О т в е т. (3/7; -2/7).Ни один из приведенных ответов не удовлетворяет системе.В этом можно убедиться подставив каждое значение в оба уравнения системы. Реклама Реклама Новые вопросы в Алгебра 1. Задана пропорция 6:=y: 7. Найдите значение ху. y=3x-7 y=2 график функций5(x-2)+4(x+3)=5-x 16x(8+4)=4(x+2x)Решите уравнение Олеся купила а ручек по 10 тенге каждую и b карандашей по 5 тенге каждый. Составьте выражение для нахождения общей стоимости всех ручек и карандашей и … найдите ее значение, если а=20, a b= 25 5. На одном сте было в 25 SE меньше картофеля, чем на Етором. После того как в первый стаж веля 10 кастоделя, а на второй - 60 т, картофеля на обоих С … клата село совету. Сколько тонія картофеля было на на каждом складе Спасите!! Нужно срочно сделать, чушь не пишите!! ПОМОГИТЕ ПОЖАЛУЙСТА ОЧЕНЬ СРОЧНО ДАЮ МАКСИМАЛЬНЫЙ БАЛЛ В группе 160 детей. Из них 60% детей младшего возраста, дети среднего возраста составляют 34 от остатка. Сколько детей старшего возраста в группе. 2((х – 2) – 2(х – 1)) + 4х = 1 Не будуючи, знайти точку перетину графіків функції y=3x-4 і y=x+2 Предыдущий Следующий Реклама - это не так уж плохо Реклама - это не так уж плохо Понимаем - вы пришли сюда не за рекламой. Но она помогает нам предоставлять бесплатный доступ к Знаниям. Пожалуйста, внесите наш сайт в список разрешенных. ОК, разблокирую рекламу на Знаниях! Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Решите систему уравнений, которая на фото ВАРИАНТЫ ОТВЕТА : а) (3;-4) б) (-1;2)...

Топьскя @Топьскя

September 2021 1 4 Report

Решите систему уравнений, которая на фото
ВАРИАНТЫ ОТВЕТА : а) (3;-4) б) (-1;2) в)(1;-2) г)(-3;4)

Answers & Comments

nafanya2014

Verified answer

Умножаем первое уравнение на 4.
Получим систему
{х+3-2(у+2)=0
{3х+у=1

{x-2y=1
{3x+y=1

Умножаем второе уравнение на 2

{x-2y=1
{6x+2y=2

Складываем
7х=3
х=3/7

у=1-3х=1-(9/7)=-2/7

О т в е т. (3/7; -2/7).

Ни один из приведенных ответов не удовлетворяет системе.
В этом можно убедиться подставив каждое значение в оба уравнения системы.