Решите систему уравнений методом подстановки: 1+2(х-у)=3х-4у 10-4(х+у)=3у-3х. Created by novinova2016. algebra-ru

Решите систему уравнений методом подстановки: 1+2(х-у)=3х-4у 10-4(х+у)=3у-3х...

novinova2016 @novinova2016

August 2022 2 2 Report

Решите систему уравнений методом подстановки:
1+2(х-у)=3х-4у
10-4(х+у)=3у-3х

irinan2014

Verified answer

Решаем способом подстановки.

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AstonishedDragon $\left \{ {{1+2(x-y)=3x-4y} \atop {10-4(x+y)=3y-3x}} \right.$
$\left \{ {{1+2x-2y=3x-4y} \atop {10-4x-4y=3y-3x}} \right.$
$\left \{ {{2x-2y-3x+4y=-1} \atop {-4x-4y-3y+3x=-10}} \right.$
$\left \{ {{-x+2y=-1} \atop {-x-7y=-10}} \right.$
$\left \{ {{-x+2y=-1} \atop {x+7y=10}} \right.$
$9y=9$
$y=1$
$-x+2*1=-1$
$x=3$
$(x,y)=(3,1)$
Ответ: (x,y)=(3,1)

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