Решите систему уравнений методом подстановки
\left \{ {x^{2}+xy=6 } \atop {x-y=4}} \right.
\left \{ {x^{2}+xy=6 } \atop {x-y=4}} \right.
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Answers & Comments
2(5-4y) +7y = 8
10 - 8y +7y = 8
-y = -2
y = 2
x= 5-4*2
x = 5-8 = -3
как то так.