Решите систему уравнений методом подстановки. Можно один из двух
2)√(7-6х-у^2)=у+5
у=х-1
1)х+2у=1
2х^2+3ху-3у^2=6
2)√(7-6х-у^2)=у+5
у=х-1
1)х+2у=1
2х^2+3ху-3у^2=6
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х+2у=1
2х^2+3ху-3у^2=6
x = 1 - 2y
2(1 - 2y)² + 3*(1 - 2y)*y - 3y² = 6
x = 1 - 2y
2*(1 - 4y + 4y²) + 3*(y - 2y²) - 3y² = 6
x = 1 - 2y
2 - 8y + 8y² + 3y - 6y² - 3y² = 6
- y² - 5y - 4 = 0
y² + 5y + 4 = 0
y₁ = - 4
y₂ = - 1
y₁ = - 4
x = 1 - 2*(-4)
x₁ = 9
y₁ = - 4
y₂ = - 1
x = 1 - 2*(-1)
x₂ = 3
y₂ = - 1
Ответ: (9; - 4) ; (3; - 1)