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danec20030412
@danec20030412
August 2022
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Решите систему уравнений пожалуйста
1)y=x^2-4x+1
2x+y=4
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Answers & Comments
FireproofWolf
Во 2-ом ур-и выразим y:
y=4-2x
Подставим в 1-ое:
4-2x=x^2-4x+1
x^2-2x-3=0
D=4-4×(-3)=16
x1=2+4/2=3
x2=2-4/2=-1
Подставим x1 во 2-ое ур-е:
y1=4-2×3=-2
Подставим x2:
y2=4-2×(-1)=6
Ответ: (3; -2) (-1; 6)
2 votes
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Answers & Comments
y=4-2x
Подставим в 1-ое:
4-2x=x^2-4x+1
x^2-2x-3=0
D=4-4×(-3)=16
x1=2+4/2=3
x2=2-4/2=-1
Подставим x1 во 2-ое ур-е:
y1=4-2×3=-2
Подставим x2:
y2=4-2×(-1)=6
Ответ: (3; -2) (-1; 6)