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gauhar0601
@gauhar0601
August 2022
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Решите систему уравнений ( x-2y-4=0
( xy=6
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rubilovalex
X=2y+4. подставляем во второе уравнение: (2y+4)*y=6; 2y^2+4y-6=0; D=4^2-4*2*(-6)=16+48=64. y1=(-4-8)/4, y2=(-4+8)/4. y1= -3, y2=1. x1=2*(-3)+4= -6+4= -2. x2=2*1+4=2+4=6. Ответ: (-2:-3), (6:1).
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