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NLOforYou
@NLOforYou
July 2022
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Решите систему уравнений :
x^2-2xy-y^2=1
х+у=2
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W1NSON
Запишем 2-е уравнение так:
x^2-2xy+y^2=16, (х-у) ^2=16,
очевидно, две возможности:
1) x-y=4, 2) x-y=-4.
1) x=1, y=-3; 2) x=-3, y=1.
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Answers & Comments
x^2-2xy+y^2=16, (х-у) ^2=16,
очевидно, две возможности:
1) x-y=4, 2) x-y=-4.
1) x=1, y=-3; 2) x=-3, y=1.