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vonelvkynyo
@vonelvkynyo
July 2022
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Решите систему уравнений x^2+3xy+y^2=11
2x+y=3
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Juliana500
X²+3xy+y²=11 x²+3x(3-2x)+(3-2x)²=11 x²+9x-6x²+9-12x+4x²=11 x²+3x+2=0
2x+y=3 y=3-2x
x²+3x+2=0 D=1
x₁=-2 y₁=3-2*(-2)=7
x₂=-1 y₂=3-2*(-1)=5.
Ответ: x₁=-2 y₁=7
x₂=-1 y₂=5.
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Answers & Comments
2x+y=3 y=3-2x
x²+3x+2=0 D=1
x₁=-2 y₁=3-2*(-2)=7
x₂=-1 y₂=3-2*(-1)=5.
Ответ: x₁=-2 y₁=7
x₂=-1 y₂=5.