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Linda241
@Linda241
July 2022
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решите систему уравнений
2х+3(х+у)=11, 7(х+3у) - 6х=-59
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miron2077
Verified answer
2х+3х+3у=11
7х+21у-6х=-59
5х+3у=11
х+21у=-59
домножим первое на -7
-35х-21у=-77
х+21у=-59
сложим
-34х=-136
х=4
4+21у=-59
21у=-63
у=3
2 votes
Thanks 4
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Answers & Comments
Verified answer
2х+3х+3у=117х+21у-6х=-59
5х+3у=11
х+21у=-59
домножим первое на -7
-35х-21у=-77
х+21у=-59
сложим
-34х=-136
х=4
4+21у=-59
21у=-63
у=3