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Zarubit
@Zarubit
July 2022
1
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Решите систему уравнений
2x - y = 6,
2x² + y² = 66.
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байонна
-y=6-2x
y=2x-6
подставим во второе
2x^2+(2x-6)^2=66
2x^2+4x^2-24x+36-66=0
6x^2-24x-30=0
x^2-4x-5=0
дискриминант=4^2-4*1*(-5)=16+20=36
x1=-1
x2=5
если Х1=-1, то у1=-8
если х2=5, то у2=4
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Answers & Comments
y=2x-6
подставим во второе
2x^2+(2x-6)^2=66
2x^2+4x^2-24x+36-66=0
6x^2-24x-30=0
x^2-4x-5=0
дискриминант=4^2-4*1*(-5)=16+20=36
x1=-1
x2=5
если Х1=-1, то у1=-8
если х2=5, то у2=4