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gadel2012
@gadel2012
July 2022
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Решите систему уравнений:4x+y=-3
-y-x^2=6
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tenderd
4x+y=-3
+
-y-x^2=6
4x-x^2=3
-x^2-4x-3=0 умножим на -1
x^2+4x+3=0
D=-4^2-4*3=4=2^2
x1= -4+2/2=-1
x2=-4-2/2=-3
y1=-3-4x=-3-4*(-1)=1
y2=-3-4*(-3)=9
ответ(-1,1)(-3,9)
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gadel2012
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Answers & Comments
+
-y-x^2=6
4x-x^2=3
-x^2-4x-3=0 умножим на -1
x^2+4x+3=0
D=-4^2-4*3=4=2^2
x1= -4+2/2=-1
x2=-4-2/2=-3
y1=-3-4x=-3-4*(-1)=1
y2=-3-4*(-3)=9
ответ(-1,1)(-3,9)