х=2+у
у²-2у(2+у) - (2+у)²= -28
у²-4у-2у²-4-4у-у²+28=0
у²+4у-12=0
д=64. у1=2; х1=4
у2= -6; х2= -4
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
х=2+у
у²-2у(2+у) - (2+у)²= -28
у²-4у-2у²-4-4у-у²+28=0
у²+4у-12=0
д=64. у1=2; х1=4
у2= -6; х2= -4