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Kat1524
@Kat1524
July 2022
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решите систему x - y = 2 и 2 x - y в квадрате = 5
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Хоукай
X-y =2
2x-y² = 5
x = 2+y
2(2+y) - y² = 5
x = 2+y
-y² + 2y + 4 - 5 = 0
y² - 2y +1 =0
D = 2² -4 = 0
y = 2/2 = 1
x = 2 + 1 = 3
y = 1
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Answers & Comments
2x-y² = 5
x = 2+y
2(2+y) - y² = 5
x = 2+y
-y² + 2y + 4 - 5 = 0
y² - 2y +1 =0
D = 2² -4 = 0
y = 2/2 = 1
x = 2 + 1 = 3
y = 1