решите систему!ПОЖАЛУЙСТА 2x^2 +y^2=36 8x^2+4x^2=36x. Created by Dashka153. algebra-ru

решите систему!ПОЖАЛУЙСТА 2x^2 +y^2=36 8x^2+4x^2=36x...

Dashka153 @Dashka153

July 2022 1 4 Report

решите систему!ПОЖАЛУЙСТА
2x^2 +y^2=36
8x^2+4x^2=36x

Answers & Comments

mmb1

Verified answer

2x^2 +y^2=36
8x^2+4x^2=36x
-----------------
умножаем первое на 4 и вычитаем второе
8x^2+4y^2=36*4
8x^2+4y^2-8x^2-4y^2=36*4-36x
36*4-36x=0
x=4
2*16+y^2=36
y^2=4
y=2
y=-2
ответ 4 2 4 -2

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Dashka153 спасибо большое!

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