Решите системы неравенств: а) 3x+9>0, x-5= 3, 3y-1

Vopros1001 @Vopros1001

July 2022 1 11 Report

Решите системы неравенств:
а) 3x+9>0,
x-5<1;
б) 2-у >= 3,
3y-1<=2.

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Universalka

Verified answer

$1)\left \{ {{3x+9>0} \atop {x-5-9} \atop {x-3} \atop {x$

$2)\left \{ {{2-y\geq3 } \atop {3y-1\leq2 }} \right.\\\\\left \{ {{-y\geq1 } \atop {3y\leq3}} \right.\\\\\left \{ {{y\leq-1 } \atop {y\leq 1}} \right.\Rightarrow y\leq-1\\\\Otvet:\boxedx\in(-\infty;-1]$

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