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madya2001
@madya2001
August 2022
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Решите системы способом подстановки :
А)х+у=6
х^2-у=14
Б)3х-у=5
х^2+у=13
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shakhzodkurambaev
A) y = x² - 14; x + x² - 14 = 6 => x² + x - 20 = 0; по Виету: x₁ + x₂ = -1; x₁ * x₂ = -20 => x₁ = -5 ; x₂= 4
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madya2001
Что насчет второго?
shakhzodkurambaev
y = 3x - 5; x² + 3x - 5 = 13 => x² + 3x -18 = 0; x₁ + x₂ = -3; x₁ * x₂ = -18 => x₁ = -6 ; x₂= 3
madya2001
Спасибо большое: )
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