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vladshved98
@vladshved98
July 2022
2
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РЕШИТЕ СРОЧНО
17-х ≤11
3(2-х)+8<-12
2х >17
2,5(2-у) ≤ 1,5(у-4)
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aliyas1
17-х ≤11
17-11 ≤x
6 ≤x
[6;+бескон]
3(2-х)+8<-12
6-3х+8<-12
-3х<-12-14
-3х<-26
х>26/3
х>8 2/3
2х >17
х>17/2
х>8 1/2
2,5(2-у) ≤ 1,5(у-4)
5-2,5у≤1,5у-6
-2,5у-1,5у≤-6-5
-4у≤-11
11/4≤у
2 3/4≤у
1 votes
Thanks 0
aliyas1
Пишу с сотки, знаков неравенств нет поэтому наоборот написаны. Но ответы правильные
anassstass
____________________
0 votes
Thanks 0
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Answers & Comments
17-11 ≤x
6 ≤x
[6;+бескон]
3(2-х)+8<-12
6-3х+8<-12
-3х<-12-14
-3х<-26
х>26/3
х>8 2/3
2х >17
х>17/2
х>8 1/2
2,5(2-у) ≤ 1,5(у-4)
5-2,5у≤1,5у-6
-2,5у-1,5у≤-6-5
-4у≤-11
11/4≤у
2 3/4≤у