Решите срочно номер 4. Created by solovyev1511200. algebra-ru

Решите срочно номер 4...

August 2021 1 4 Report

Решите срочно номер 4

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Dushzhanov987 №4
$\frac{b^2+8b+16}{4b+16} = \frac{(b+4)^2}{4(b+4)} = \frac{b+4}{4}$

$\frac{b^2-16}{2b+8} = \frac{(b-4)(b+4)}{2(b+4)} = \frac{b-4}{2}$

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