Ответ:
Объяснение:
1) a) =>
б) =>
в)
г)
2) a)
б)
3) a)
корней нет
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Answers & Comments
Ответ:
Объяснение:
1) a)
=> 
б)
=> 
в)
г)
2) a)
б)
3) a)
б)
корней нет
в)
г)