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Ответ:

(х+2)(х–1)(х–3)=(x2+2х–х–2)(х–3)=(x2+х–2)(х–3)=

=x3+x2–2x–3x2–3x+6=x3–2x2–5x+6.

Объяснение:

(х+2)(х–1)(х–3)=(x2+2х–х–2)(х–3)=(x2+х–2)(х–3)=

=x3+x2–2x–3x2–3x+6=x3–2x2–5x+6.