tERROR418

Ответ:

X = π/3 + 4πn, n∈Z

X = 3π + 4πn , n∈Z

под знаком системы

Пошаговое объяснение:

x/2 + π/6 = arccos(1/2)

11π/6 - x/2 = arccos(1/2)

x/2 + π/6 = π/3 + 2πn

11π/6 - x/2 = π/3 + 2πn

x = π/3 + 4πn, n∈Z

x = 3π + 4πn , n∈Z

Буква д:

x = 7π/8 + πn, n∈Z

2x - π/4 = 3π/2 + 2πn, n∈Z

2x = 7π/4 + + 2πn, n∈Z

x = 7π/8 + πn, n∈Z