1. ∠BAC = 180 -123 = 57°
∠B = 180-(57+31) = 180- 88 =92°
3. ∠B= 180 - 110 = 70
т.к. AB=BC⇒ΔABC-равнобедренный ⇒ ∠А=∠С
∠А=∠С=180-70=110°
∠А=∠С = 110÷2 = 55°
2. АС = 15-10=5см
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Answers & Comments
1. ∠BAC = 180 -123 = 57°
∠B = 180-(57+31) = 180- 88 =92°
3. ∠B= 180 - 110 = 70
т.к. AB=BC⇒ΔABC-равнобедренный ⇒ ∠А=∠С
∠А=∠С=180-70=110°
∠А=∠С = 110÷2 = 55°
2. АС = 15-10=5см