решите уравнение: 1) (х-5)^2+4x=25 2) (x+6)(x-7)= -x+7 3) 6x(0.5+3x)-15x^2 = 0
4) (4-x)(4+x)=x^2-2
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4) (4-x)(4+x)=x^2-2
помогите пж)))))
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Verified answer
1) (x-5)^2+4x=25 2) (x+6)(x-7)=-x+7 3)6x(0.5+3x)-15x^2=0x^2-10x+25+4x-25=0 x^2-7x+6x-42+x-7=0 3x+18x^2-15x^2=0
x^2-6x=0 x^2=49 3x^2+3x=0
x(x-6)=0 x= -7 и x=7 x=0 и x= -1
x=0 и x=6
4)(4-x)(4+x)=x^2-2
16-x^2-x^2+2=0
-2x^2+18=0
x^2=9
x=3 x= -3
Verified answer
X^2-10x+25+4x-25=0x^2-6x=0
x(x-6)=0
x1=0
x2=6
x^2-7x+6x-42+x-7=0
x^2-49=0
x^2=49
x1=7
x2=-7
3x+18x^2-15x^2=0
3x+3x^2=0
3x(1+x)=0
x1=0
x2=-1
16-x^2-x^2+2=0
-2x^2+18=0
-2x^2=-18
x^2=9
x1=3
x2=-3