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romansalomatov1
@romansalomatov1
July 2022
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Решите уравнение:
(1+2sinx)(3-2tgx)=0
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alex080297
Verified answer
(1+2sinx)(3-2tgx)=0
1+2sinx=0 3-2tgx=0
2sinx=-1 2tgx=3
sinx=-1/2 tgx=3/2
x=7pi/6+2πk x=arctg(3/2)+πk
x=11pi/6+2πk
Ответ:x=7pi/6+2πk;x=11pi/6+2πk;x=arctg(3/2)+πk
1 votes
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Answers & Comments
Verified answer
(1+2sinx)(3-2tgx)=01+2sinx=0 3-2tgx=0
2sinx=-1 2tgx=3
sinx=-1/2 tgx=3/2
x=7pi/6+2πk x=arctg(3/2)+πk
x=11pi/6+2πk
Ответ:x=7pi/6+2πk;x=11pi/6+2πk;x=arctg(3/2)+πk