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radchenkoalinka
@radchenkoalinka
July 2022
2
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Решите уравнение
1)(2y-1)(1-y)+(y+1)(2y-3)=0
2)(x-1)(x-3)=(x-2)(x+3)
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Tisida
Verified answer
2y-2y^2-1+y+2y^2-3y+2y-3=0
сокращаем
2у-4=0
2y=4
y=2
0 votes
Thanks 1
Юленька194
1)(2y-1)(1-y)+(y+1)(2y-3)=0
2y-2y
²
-1
+y+2y²-3y
+2y-3=0
2y-4=0
2y=4
y=2
2)(x-1)(x-3)=(x-2)(x+3)
x
²
-3x-x+3=
x²
+3x-2x-6
-4x+3=x-6
5x=9
x=
x=
x=1,8
2 votes
Thanks 0
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Answers & Comments
Verified answer
2y-2y^2-1+y+2y^2-3y+2y-3=0сокращаем
2у-4=0
2y=4
y=2
2y-2y²-1+y+2y²-3y+2y-3=0
2y-4=0
2y=4
y=2
2)(x-1)(x-3)=(x-2)(x+3)
x²-3x-x+3=x²+3x-2x-6
-4x+3=x-6
5x=9
x=
x=
x=1,8