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AzisForp
@AzisForp
August 2022
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Решите уравнение:
1)40x-50=6-3x ;
2) (3x-2) * (x-3) = 20 ;
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daryastanchik27
1) 40x-50=6-3x
43x=56
x=56/43≈1,30
2) (3x-2)*(x-3)=20
3x²-9x-2x+6=20
3x²-11x-14=20
D=b²-4ac
D=121-4*3*(-14)=289=17²
x1,2=
x1=1
x2=28/6=14/3
0 votes
Thanks 0
daryastanchik27
Отметьте решение лучшее(коронкой), пожалуйста
Myamik
1)40х+3х=6+50
43х=56|:43
Х=1 целая 13/43
2)3х^2-9х-2х+6=20
3х^2-11х-14=0
Д=121+4*3*14=√289=17
Х=11+17/6=4целых 2/3
Х= 11-17/6= -1
1 votes
Thanks 0
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Answers & Comments
43x=56
x=56/43≈1,30
2) (3x-2)*(x-3)=20
3x²-9x-2x+6=20
3x²-11x-14=20
D=b²-4ac
D=121-4*3*(-14)=289=17²
x1,2=
x1=1
x2=28/6=14/3
43х=56|:43
Х=1 целая 13/43
2)3х^2-9х-2х+6=20
3х^2-11х-14=0
Д=121+4*3*14=√289=17
Х=11+17/6=4целых 2/3
Х= 11-17/6= -1